2017年8月30日 · 165 Since 3, 5 and 11 are all prime numbers their least common multiple (lcm) is: 3 xx 5 xx 11 = 165

240 For LCM problems, I like to do a prime factorization first: 3=3 5=5 15=3xx5 16=2xx2xx2xx2 And now the LCM will have all the primes listed. So - we have a 3 from the 3. We have a 5 from the 5. The 3 and 5 of the 15 are already listed, so we can move on to the 16 which has four 2s. So the LCM is: 3xx5xx2xx2xx2xx2=15xx16=240 3 xx80=240 5xx48=240 15xx16=240

2018年2月13日 · The answer is 70. To find the LCM (Lowest common multiple) of a set of numbers, you first find the multiples of each number and then identify the smallest common one among the set. In this case, using 5, 7, and 10. The smallest common multiple of each would be 70. If we find the multiples of each of the numbers, we can see that no other number before 70 is common to all of them. Multiples of 5 ...

2017年6月25日 · LCM= 2xx2xx3xx5xx11 = 660 5 and 11 are both prime and share no common factors. The prime factors of 12 are 2xx2xx3 There are no common factors between any of these numbers, so the LCM will consist of all of their factors: LCM= 2xx2xx3xx5xx11 = 660 11 and 12 are consecutive numbers and their LCM is immediately their product.

2018年5月7日 · The LCM is 30. LCM means least common multiple. We can determine the least common multiple by listing the multiples of each number, and then identifying the lowest multiple that they have in common. 5: 5,10,15,20,25,color(red)30,35,40... 6: 6,12,18,24,color(red)30,36,42... 15: 15,color(red)30,45,60... The lowest multiple in common is 30. "LCM(5,6,15)"=30. You can also use prime factorization ...

2016年10月5日 · 33 Since both 3 and 11 are prime numbers, their LCM is their product. LCM = 3xx11=33. Prealgebra . Science ...

2016年12月11日 · 30 3 is a prime number and 3 is not a factor of 10. Therefore the LCM will be product of 3 and 10. 3 xx 10 = 30 This can also be shown by writing the multiple of 10 (the bigger number, until one is found that is a multiple of 3. 10" "20" "30 The third multiple is …

2016年11月16日 · The factors are as follows 7=7*1 4=2^2 3=3*1 6=2*3 The LCM is 7*2^2*3=7*4*3=84. How can you find the least common multiple using prime factorization?

2015年10月13日 · 90 * x^2 * y^3 Multiply the highest powers of x and y (2 & 3 in this case; x^2 in 15x^2y^3 is greater than x in 18 * x * y^2, so consider x^2; Similarly y^3 in 15 * x^2 * y^3 is greater than y^2 in 18 * x * y^2, so consider y^3. So the variable part is x^2 * y^3. Coming to constant part, to find out the LCM between 15 & 18, divide both of them by 3, which is a factor of both So {15, 18} = 3 {5 ...

2017年1月17日 · #color(brown)("Observation 3")# Consider the 2 from 12: the multiple of 12 has to end in 0. note the least value times 12 to give 0 as a last digit is 5 and #5xx12=60# But 60 does not divide exactly by 8 so using observation 2 multiply 60 by 2 giving 120 +++++